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(N)=0.4N^2+9.6N+11
We move all terms to the left:
(N)-(0.4N^2+9.6N+11)=0
We get rid of parentheses
-0.4N^2+N-9.6N-11=0
We add all the numbers together, and all the variables
-0.4N^2-8.6N-11=0
a = -0.4; b = -8.6; c = -11;
Δ = b2-4ac
Δ = -8.62-4·(-0.4)·(-11)
Δ = 56.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.6)-\sqrt{56.36}}{2*-0.4}=\frac{8.6-\sqrt{56.36}}{-0.8} $$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.6)+\sqrt{56.36}}{2*-0.4}=\frac{8.6+\sqrt{56.36}}{-0.8} $
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